(x^2+2x+1)(x-5)=0

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Solution for (x^2+2x+1)(x-5)=0 equation: 


Simplifying
(x2 + 2x + 1)(x + -5) = 0

Reorder the terms:
(1 + 2x + x2)(x + -5) = 0

Reorder the terms:
(1 + 2x + x2)(-5 + x) = 0

Multiply (1 + 2x + x2) * (-5 + x)
(1(-5 + x) + 2x * (-5 + x) + x2(-5 + x)) = 0
((-5 * 1 + x * 1) + 2x * (-5 + x) + x2(-5 + x)) = 0
((-5 + 1x) + 2x * (-5 + x) + x2(-5 + x)) = 0
(-5 + 1x + (-5 * 2x + x * 2x) + x2(-5 + x)) = 0
(-5 + 1x + (-10x + 2x2) + x2(-5 + x)) = 0
(-5 + 1x + -10x + 2x2 + (-5 * x2 + x * x2)) = 0
(-5 + 1x + -10x + 2x2 + (-5x2 + x3)) = 0

Combine like terms: 1x + -10x = -9x
(-5 + -9x + 2x2 + -5x2 + x3) = 0

Combine like terms: 2x2 + -5x2 = -3x2
(-5 + -9x + -3x2 + x3) = 0

Solving
-5 + -9x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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